NYT Pips answers — Tuesday, November 3, 2026
The NYT Pips answers for Tuesday, November 3, 2026: the solved easy, medium and hard boards are below, with the squares of every domino listed and three hints per level if you would rather solve it yourself.
Easy Pips answer
Pips row by row, top to bottom (· is a gap in the board)
1 2 2 0 1 0 3 3 1 · · 3
Each domino and its squares
- 1–2 — 1 at row 1, column 1, 2 at row 1, column 2
- 2–0 — 2 at row 1, column 3, 0 at row 1, column 4
- 1–1 — 1 at row 2, column 1, 1 at row 3, column 1
- 3–3 — 3 at row 2, column 4, 3 at row 3, column 4
- 0–3 — 0 at row 2, column 2, 3 at row 2, column 3
Medium Pips answer
Pips row by row, top to bottom (· is a gap in the board)
6 5 4 · · 3 5 1 3 · 3 2 2 0 · · · 4 4 4
Each domino and its squares
- 6–3 — 6 at row 1, column 1, 3 at row 2, column 1
- 4–1 — 4 at row 1, column 3, 1 at row 2, column 3
- 3–2 — 3 at row 3, column 1, 2 at row 3, column 2
- 4–4 — 4 at row 4, column 4, 4 at row 4, column 5
- 3–0 — 3 at row 2, column 4, 0 at row 3, column 4
- 4–2 — 4 at row 4, column 3, 2 at row 3, column 3
- 5–5 — 5 at row 1, column 2, 5 at row 2, column 2
Hard Pips answer
Pips row by row, top to bottom (· is a gap in the board)
2 1 5 5 1 · 5 0 0 · 0 4 0 6 · · 6 4 2 2 · · 3 3 0 3 · 1 1 3 2 4 5 5 · 3
Each domino and its squares
- 5–5 — 5 at row 6, column 3, 5 at row 6, column 4
- 3–3 — 3 at row 5, column 6, 3 at row 6, column 6
- 3–2 — 3 at row 5, column 2, 2 at row 4, column 2
- 0–6 — 0 at row 3, column 1, 6 at row 3, column 2
- 2–0 — 2 at row 4, column 1, 0 at row 5, column 1
- 0–1 — 0 at row 2, column 2, 1 at row 1, column 2
- 0–5 — 0 at row 2, column 3, 5 at row 1, column 3
- 1–5 — 1 at row 1, column 5, 5 at row 1, column 4
- 2–5 — 2 at row 1, column 1, 5 at row 2, column 1
- 3–6 — 3 at row 4, column 5, 6 at row 3, column 5
- 0–4 — 0 at row 2, column 5, 4 at row 2, column 6
- 1–1 — 1 at row 5, column 4, 1 at row 5, column 5
- 2–4 — 2 at row 6, column 1, 4 at row 6, column 2
- 3–4 — 3 at row 4, column 6, 4 at row 3, column 6
Rather solve it yourself?
Three hints per level, the last one placing the second domino.
Easy
5 dominoes, 5 regions, a 3×4 grid: that's the easy puzzle for November 3, 2026. The mix is 2 "all equal", 1 "greater than", 2 free regions. The "=" pair at row 1, column 2 needs two identical pips. The rack holds 2 doubles, 2 blank halves.
Hint 1: where to start
The long "all equal" region at row 1, column 1 (3 cells) takes one number throughout. Every half with that number on the rack is a candidate for it.
Hint 2: first domino
The 1–2 goes there: 1 on row 1, column 1, 2 on row 1, column 2.
Hint 3: second domino
Next, the 2–0 goes at row 1, column 3 → row 1, column 4. That leaves 3 dominoes, each with far fewer homes.
Medium
7 dominoes, 8 regions, a 4×5 grid: that's the medium puzzle for November 3, 2026. You're working with 4 sum regions, 1 "all equal", 2 "greater than". Another early foothold: the single cell at row 3, column 1 is marked 3, so it can only hold a 3. The rack holds 2 doubles, 1 blank half, 1 six.
Hint 1: where to start
Row 1, column 3 is a region of its own with target 4: that cell is a 4. Only dominoes carrying a 4 can reach it.
Hint 2: first domino
The 4–1 goes there: 4 on row 1, column 3, 1 on row 2, column 3.
Hint 3: second domino
Next, the 3–2 goes at row 3, column 1 → row 3, column 2. That leaves 5 dominoes, each with far fewer homes.
Hard
The hard Pips has 28 cells to cover with 14 dominoes, split into 20 regions. The mix is 8 sum regions, 2 "all equal", 4 "less than", 1 "greater than", 4 free regions. Another early foothold: row 2, column 3 is a region of its own with target 0: that cell is a 0. Keep in mind that a one-cell region at row 3, column 1 asks for 0, which fixes that cell outright. Rack check: 3 doubles, 5 blank halves, 2 sixes.
Hint 1: where to start
A one-cell region at row 2, column 2 asks for 0, which fixes that cell outright. Find the domino with a 0 that fits there.
Hint 2: first domino
The 0–1 goes there: 0 on row 2, column 2, 1 on row 1, column 2.
Hint 3: second domino
Next, the 0–5 goes at row 2, column 3 → row 1, column 3. That leaves 12 dominoes, each with far fewer homes.