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NYT Pips answers — Sunday, October 4, 2026
Pips #413 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Rodolfo Kurchan · Hard by Rodolfo Kurchan
Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first, the answer only when you want it.
Also today: LinkedIn games answers — Zip, Pinpoint, Crossclimb, Mini Sudoku, Patches and Wend.
Easy Pips answer — October 4, 2026
3×3 board · 4 dominoes · 4 regions · by Ian Livengood
Easy is 4 regions on a 3×3 grid, filled by 4 dominoes. You're working with 3 sum regions, 1 "all equal". Another early foothold: two cells at row 1, column 3 total 9. The rack holds 1 double, 1 six.
Hints
Hint 1: where to start
At row 1, column 1 two cells must match. That is a double, or matching halves from two dominoes.
Hint 2: first domino
The 2–2 goes there: 2 on row 1, column 1, 2 on row 2, column 1.
Hint 3: second domino
Next, the 4–2 goes at row 1, column 3 → row 1, column 2. That leaves 2 dominoes, each with far fewer homes.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; 9 must add up to 9; 7 must add up to 7.
Solution as text
2 2 4 2 · 5 5 6 3
- 4–2 — 4 at row 1, column 3, 2 at row 1, column 2
- 2–2 — 2 at row 1, column 1, 2 at row 2, column 1
- 5–6 — 5 at row 3, column 1, 6 at row 3, column 2
- 3–5 — 3 at row 3, column 3, 5 at row 2, column 3
Medium Pips answer — October 4, 2026
5×4 board · 7 dominoes · 9 regions · by Rodolfo Kurchan
Medium is 9 regions on a 5×4 grid, filled by 7 dominoes. By rule type: 3 sum regions, 1 "all equal", 1 "less than", 1 "greater than", 2 free regions. Another early foothold: a one-cell region at row 5, column 3 asks for 2, which fixes that cell outright. Rack check: 1 double, 1 six.
Hints
Hint 1: where to start
The single cell at row 4, column 1 is marked 1, so it can only hold a 1. Find the domino with a 1 that fits there.
Hint 2: first domino
The 5–1 goes there: 5 on row 4, column 2, 1 on row 4, column 1.
Hint 3: second domino
Next, the 2–3 goes at row 5, column 3 → row 4, column 3. That leaves 5 dominoes, each with far fewer homes.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: <3 must add up to less than 3; ≠ must all be different; >3 must add up to more than 3; = must all be the same number; 1 must add up to 1.
Solution as text
· · · 2 · 3 5 4 6 5 5 5 1 5 3 3 · · 2 1
- 1–3 — 1 at row 5, column 4, 3 at row 4, column 4
- 4–2 — 4 at row 2, column 4, 2 at row 1, column 4
- 6–5 — 6 at row 3, column 1, 5 at row 3, column 2
- 5–3 — 5 at row 2, column 3, 3 at row 2, column 2
- 5–1 — 5 at row 4, column 2, 1 at row 4, column 1
- 2–3 — 2 at row 5, column 3, 3 at row 4, column 3
- 5–5 — 5 at row 3, column 3, 5 at row 3, column 4
Hard Pips answer — October 4, 2026
6×6 board · 14 dominoes · 18 regions · by Rodolfo Kurchan
The hard Pips has 28 cells to cover with 14 dominoes, split into 18 regions. Rules on the board: 8 sum regions, 2 "all equal", 2 "less than", 1 "greater than", 3 free regions. The single cell at row 2, column 6 is marked 2, so it can only hold a 2. Keep in mind that the single cell at row 5, column 5 is marked 0, so it can only hold a 0. The rack holds 2 doubles, 4 blank halves, 1 six.
Hints
Hint 1: where to start
Row 2, column 2 is a region of its own with target 2: that cell is a 2. Only dominoes carrying a 2 can reach it.
Hint 2: first domino
First domino: 2–0, covering row 2, column 2 (2) and row 1, column 2 (0).
Hint 3: second domino
Second: 2–3 on row 2, column 6 and row 1, column 6. Check the other 12 against the regions they could still fill.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: 3 must add up to 3; 8 must add up to 8; <2 must add up to less than 2; = must all be the same number; 2 must add up to 2.
Solution as text
3 0 5 1 0 3 4 2 3 5 4 2 4 · · · · 2 4 3 · 1 · 2 · 6 1 5 0 2 0 3 3 · 5 4
- 6–3 — 6 at row 5, column 2, 3 at row 4, column 2
- 4–2 — 4 at row 6, column 6, 2 at row 5, column 6
- 5–1 — 5 at row 5, column 4, 1 at row 4, column 4
- 0–3 — 0 at row 6, column 1, 3 at row 6, column 2
- 4–5 — 4 at row 2, column 5, 5 at row 2, column 4
- 5–3 — 5 at row 1, column 3, 3 at row 2, column 3
- 2–3 — 2 at row 2, column 6, 3 at row 1, column 6
- 1–3 — 1 at row 5, column 3, 3 at row 6, column 3
- 2–0 — 2 at row 2, column 2, 0 at row 1, column 2
- 4–4 — 4 at row 3, column 1, 4 at row 4, column 1
- 3–4 — 3 at row 1, column 1, 4 at row 2, column 1
- 2–2 — 2 at row 3, column 6, 2 at row 4, column 6
- 0–5 — 0 at row 5, column 5, 5 at row 6, column 5
- 1–0 — 1 at row 1, column 4, 0 at row 1, column 5
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