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NYT Pips answers — Monday, August 17, 2026
Pips #365 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Ian Livengood · Hard by Rodolfo Kurchan
Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.
Easy Pips answer — August 17, 2026
3×4 board · 5 dominoes · 6 regions · by Ian Livengood
5 dominoes, 6 regions, a 3×4 grid — that's the easy puzzle for August 17, 2026. You're working with 1 sum region, 2 "all equal", 2 "less than", 1 free region. The way in: the "=" region starting at row 1, column 2 has 3 cells that must all match — every 6 in the puzzle should come here.. After that, the "<1" region at row 1, column 1 leaves almost no room: every cell must be 0.. Rack check: 2 blank halves, 3 sixes.
Hints
Hint 1 — where to start
The "=" region starting at row 1, column 2 has 3 cells that must all match — every 6 in the puzzle should come here.
Hint 2 — first domino
Place the 0–6 domino with its 0 at row 1, column 1 and its 6 at row 1, column 2.
Hint 3 — second domino
Next, the 1–0 goes at row 3, column 2 → row 3, column 1. From there the rest should fall into place.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: <1 must add up to less than 1; = must all be the same number; 7 must add up to 7.
Solution as text
0 6 6 2 · · 6 5 0 1 1 4
- 6–1 — 6 at row 2, column 3, 1 at row 3, column 3
- 1–0 — 1 at row 3, column 2, 0 at row 3, column 1
- 2–6 — 2 at row 1, column 4, 6 at row 1, column 3
- 0–6 — 0 at row 1, column 1, 6 at row 1, column 2
- 5–4 — 5 at row 2, column 4, 4 at row 3, column 4
Medium Pips answer — August 17, 2026
4×6 board · 7 dominoes · 5 regions · by Ian Livengood
Medium today is a 4×6 board with 7 dominoes and 5 regions. Rules on the board: 1 sum region, 1 "all equal", 1 "less than", 2 "greater than". Best foothold — the "=" region starting at row 4, column 3 has 4 cells that must all match — every 5 in the puzzle should come here.. Rack check: 3 doubles, 4 blank halves, 1 six.
Hints
Hint 1 — where to start
The "=" region starting at row 4, column 3 has 4 cells that must all match — every 5 in the puzzle should come here.
Hint 2 — first domino
Place the 5–2 domino with its 5 at row 4, column 3 and its 2 at row 3, column 3.
Hint 3 — second domino
Next, the 2–3 goes at row 2, column 3 → row 2, column 2. From there the rest should fall into place.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: <9 must add up to less than 9; 2 must add up to 2; >2 must add up to more than 2; >3 must add up to more than 3; = must all be the same number.
Solution as text
· · · 2 · · 0 3 2 2 · · 0 0 2 0 · · · 6 5 5 5 5
- 2–3 — 2 at row 2, column 3, 3 at row 2, column 2
- 6–0 — 6 at row 4, column 2, 0 at row 3, column 2
- 5–5 — 5 at row 4, column 5, 5 at row 4, column 6
- 0–0 — 0 at row 2, column 1, 0 at row 3, column 1
- 2–2 — 2 at row 1, column 4, 2 at row 2, column 4
- 0–5 — 0 at row 3, column 4, 5 at row 4, column 4
- 5–2 — 5 at row 4, column 3, 2 at row 3, column 3
Hard Pips answer — August 17, 2026
7×8 board · 13 dominoes · 12 regions · by Rodolfo Kurchan
13 dominoes, 12 regions, a 7×8 grid — that's the hard puzzle for August 17, 2026. Rules on the board: 7 sum regions, 1 "all equal", 1 "less than", 3 "greater than". Best foothold — the single cell at row 7, column 3 is marked 4, so it can only hold a 4. After that, the two-cell region at row 5, column 1 adds to 0: both cells must be 0. Rack check: 2 doubles, 5 blank halves, 3 sixes.
Hints
Hint 1 — where to start
The single cell at row 7, column 3 is marked 4, so it can only hold a 4. Find the domino with a 4 that fits there.
Hint 2 — first domino
Place the 1–4 domino with its 1 at row 7, column 2 and its 4 at row 7, column 3.
Hint 3 — second domino
Next, the 0–2 goes at row 5, column 1 → row 4, column 1. From there the rest should fall into place.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: >10 must add up to more than 10; <3 must add up to less than 3; >9 must add up to more than 9; 4 must add up to 4; 0 must add up to 0.
Solution as text
5 0 0 4 · · · · 6 · · 6 · · · · 2 · · 0 · · · · 2 · · 4 · · · · 0 · · 2 · 3 1 1 0 · · 2 · 1 · 1 3 1 4 2 · 5 6 1
- 0–2 — 0 at row 5, column 1, 2 at row 4, column 1
- 0–3 — 0 at row 6, column 1, 3 at row 7, column 1
- 0–4 — 0 at row 1, column 3, 4 at row 1, column 4
- 0–5 — 0 at row 1, column 2, 5 at row 1, column 1
- 0–6 — 0 at row 3, column 4, 6 at row 2, column 4
- 1–1 — 1 at row 5, column 8, 1 at row 6, column 8
- 1–3 — 1 at row 5, column 7, 3 at row 5, column 6
- 1–4 — 1 at row 7, column 2, 4 at row 7, column 3
- 1–5 — 1 at row 6, column 6, 5 at row 7, column 6
- 1–6 — 1 at row 7, column 8, 6 at row 7, column 7
- 2–2 — 2 at row 6, column 4, 2 at row 7, column 4
- 2–4 — 2 at row 5, column 4, 4 at row 4, column 4
- 2–6 — 2 at row 3, column 1, 6 at row 2, column 1
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