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NYT Pips answers — Saturday, August 15, 2026
Pips #363 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Ian Livengood · Hard by Rodolfo Kurchan
Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.
Easy Pips answer — August 15, 2026
3×4 board · 5 dominoes · 4 regions · by Ian Livengood
Easy today is a 3×4 board with 5 dominoes and 4 regions. Rules on the board: 2 sum regions, 2 "all equal". Best foothold — the single cell at row 3, column 3 is marked 5, so it can only hold a 5. After that, the "=" region starting at row 1, column 3 has 4 cells that must all match — every 6 in the puzzle should come here.. Rack check: 3 doubles, 1 blank half, 4 sixes.
Hints
Hint 1 — where to start
The single cell at row 3, column 3 is marked 5, so it can only hold a 5. Find the domino with a 5 that fits there.
Hint 2 — first domino
Place the 6–5 domino with its 6 at row 2, column 3 and its 5 at row 3, column 3.
Hint 3 — second domino
Next, the 6–6 goes at row 1, column 3 → row 1, column 4. From there the rest should fall into place.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: 8 must add up to 8; = must all be the same number; 5 must add up to 5.
Solution as text
4 0 6 6 4 6 6 3 · · 5 3
- 6–5 — 6 at row 2, column 3, 5 at row 3, column 3
- 0–6 — 0 at row 1, column 2, 6 at row 2, column 2
- 4–4 — 4 at row 1, column 1, 4 at row 2, column 1
- 6–6 — 6 at row 1, column 3, 6 at row 1, column 4
- 3–3 — 3 at row 2, column 4, 3 at row 3, column 4
Medium Pips answer — August 15, 2026
5×4 board · 7 dominoes · 9 regions · by Ian Livengood
7 dominoes, 9 regions, a 5×4 grid — that's the medium puzzle for August 15, 2026. You're working with 1 sum region, 1 "all equal", 2 "less than", 3 "greater than", 2 free regions. The way in: the "=" pair at row 2, column 3 needs two identical pips — a double, or matching halves from two dominoes.. After that, the pair at row 2, column 2 adds to 6; list the ways to make 6 with the rack you have.. Rack check: 1 blank half, 4 sixes.
Hints
Hint 1 — where to start
The "=" pair at row 2, column 3 needs two identical pips — a double, or matching halves from two dominoes.
Hint 2 — first domino
Place the 4–2 domino with its 4 at row 1, column 3 and its 2 at row 2, column 3.
Hint 3 — second domino
Next, the 3–6 goes at row 2, column 2 → row 2, column 1. From there the rest should fall into place.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: >8 must add up to more than 8; >4 must add up to more than 4; 6 must add up to 6; = must all be the same number; <3 must add up to less than 3.
Solution as text
4 6 4 6 6 3 2 2 · 3 · 6 · 1 0 1 · · 2 ·
- 4–6 — 4 at row 1, column 1, 6 at row 1, column 2
- 1–3 — 1 at row 4, column 2, 3 at row 3, column 2
- 1–6 — 1 at row 4, column 4, 6 at row 3, column 4
- 6–2 — 6 at row 1, column 4, 2 at row 2, column 4
- 3–6 — 3 at row 2, column 2, 6 at row 2, column 1
- 2–0 — 2 at row 5, column 3, 0 at row 4, column 3
- 4–2 — 4 at row 1, column 3, 2 at row 2, column 3
Hard Pips answer — August 15, 2026
10×7 board · 15 dominoes · 17 regions · by Rodolfo Kurchan
15 dominoes, 17 regions, a 10×7 grid — that's the hard puzzle for August 15, 2026. You're working with 3 sum regions, 3 "all equal", 1 "less than", 6 "greater than", 4 free regions. The way in: the two-cell region at row 9, column 6 adds to 0: both cells must be 0. After that, the "=" region starting at row 2, column 2 has 4 cells that must all match — every 1 in the puzzle should come here.. Rack check: 4 doubles, 7 blank halves, 5 sixes.
Hints
Hint 1 — where to start
The two-cell region at row 9, column 6 adds to 0: both cells must be 0. That's the 0–0 domino, or two 0s from different dominoes.
Hint 2 — first domino
Place the 3–0 domino with its 3 at row 9, column 5 and its 0 at row 9, column 6.
Hint 3 — second domino
Next, the 1–1 goes at row 2, column 2 → row 3, column 2. From there the rest should fall into place.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: >4 must add up to more than 4; >0 must add up to more than 0; >16 must add up to more than 16; >3 must add up to more than 3; = must all be the same number.
Solution as text
5 · 2 · 6 6 4 0 1 1 · 5 · · · 1 · · 0 0 · · 1 · · 0 · · · 0 · · 2 6 6 · · · · · · · · · 4 · · 6 · · · 4 4 · 2 · · · 4 3 3 0 · · · 5 · 4 0 ·
- 0–1 — 0 at row 5, column 2, 1 at row 4, column 2
- 4–4 — 4 at row 7, column 3, 4 at row 8, column 3
- 0–5 — 0 at row 2, column 1, 5 at row 1, column 1
- 2–1 — 2 at row 1, column 3, 1 at row 2, column 3
- 0–0 — 0 at row 3, column 5, 0 at row 3, column 6
- 6–4 — 6 at row 1, column 6, 4 at row 1, column 7
- 3–0 — 3 at row 9, column 5, 0 at row 9, column 6
- 6–2 — 6 at row 7, column 6, 2 at row 8, column 6
- 4–5 — 4 at row 9, column 3, 5 at row 10, column 3
- 1–1 — 1 at row 2, column 2, 1 at row 3, column 2
- 4–3 — 4 at row 8, column 4, 3 at row 9, column 4
- 6–5 — 6 at row 1, column 5, 5 at row 2, column 5
- 2–0 — 2 at row 5, column 5, 0 at row 4, column 5
- 6–6 — 6 at row 5, column 6, 6 at row 5, column 7
- 0–4 — 0 at row 10, column 6, 4 at row 10, column 5
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