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NYT Pips answers — Thursday, July 30, 2026

Pips #347 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Rodolfo Kurchan · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

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Easy Pips answer — July 30, 2026

4×4 board · 5 dominoes · 7 regions · by Ian Livengood

5 dominoes, 7 regions, a 4×4 grid — that's the easy puzzle for July 30, 2026. Rules on the board: 3 sum regions, 2 "all equal", 1 "less than", 1 free region. Best foothold — the single cell at row 1, column 3 is marked 5, so it can only hold a 5. After that, the single cell at row 4, column 4 is marked 5, so it can only hold a 5. Rack check: 1 double, 2 sixes.

Hints

Hint 1 — where to start

The single cell at row 1, column 3 is marked 5, so it can only hold a 5. Find the domino with a 5 that fits there.

Hint 2 — first domino

Place the 5–6 domino with its 5 at row 1, column 3 and its 6 at row 2, column 3.

Hint 3 — second domino

Next, the 5–1 goes at row 4, column 4 → row 3, column 4. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 5 must add up to 5; = must all be the same number; <4 must add up to less than 4; 10 must add up to 10.

5
=
=
<4
10
5
Solution as text
  1. 5–5 — 5 at row 4, column 1, 5 at row 4, column 2
  2. 1–6 — 1 at row 3, column 2, 6 at row 3, column 3
  3. 5–6 — 5 at row 1, column 3, 6 at row 2, column 3
  4. 5–1 — 5 at row 4, column 4, 1 at row 3, column 4
  5. 4–1 — 4 at row 2, column 1, 1 at row 2, column 2

Medium Pips answer — July 30, 2026

5×5 board · 7 dominoes · 7 regions · by Rodolfo Kurchan

Medium today is a 5×5 board with 7 dominoes and 7 regions. You're working with 3 sum regions, 1 "all equal", 1 "greater than", 2 free regions. The "=" region starting at row 3, column 3 has 3 cells that must all match — every 3 in the puzzle should come here.. After that, the pair at row 1, column 3 adds to 5; list the ways to make 5 with the rack you have.. Rack check: 1 blank half, 2 sixes.

Hints

Hint 1 — where to start

The "=" region starting at row 3, column 3 has 3 cells that must all match — every 3 in the puzzle should come here.

Hint 2 — first domino

Place the 2–3 domino with its 2 at row 3, column 2 and its 3 at row 3, column 3.

Hint 3 — second domino

Next, the 1–4 goes at row 1, column 3 → row 2, column 3. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 5 must add up to 5; 15 must add up to 15; = must all be the same number; >2 must add up to more than 2.

5
15
=
15
>2
Solution as text
  1. 1–4 — 1 at row 1, column 3, 4 at row 2, column 3
  2. 6–3 — 6 at row 2, column 4, 3 at row 3, column 4
  3. 4–5 — 4 at row 2, column 5, 5 at row 1, column 5
  4. 2–3 — 2 at row 3, column 2, 3 at row 3, column 3
  5. 0–5 — 0 at row 4, column 1, 5 at row 4, column 2
  6. 4–6 — 4 at row 5, column 2, 6 at row 5, column 3
  7. 5–3 — 5 at row 4, column 4, 3 at row 4, column 3

Hard Pips answer — July 30, 2026

8×4 board · 16 dominoes · 24 regions · by Rodolfo Kurchan

The hard board runs 8 rows by 4 columns: 16 dominoes to place across 24 regions. The mix is 21 sum regions, 3 "all equal". Best foothold — the single cell at row 1, column 1 is marked 3, so it can only hold a 3. After that, the single cell at row 1, column 2 is marked 4, so it can only hold a 4. Rack check: 5 blank halves, 1 six.

Hints

Hint 1 — where to start

The single cell at row 1, column 1 is marked 3, so it can only hold a 3. Find the domino with a 3 that fits there.

Hint 2 — first domino

Place the 1–3 domino with its 1 at row 2, column 1 and its 3 at row 1, column 1.

Hint 3 — second domino

Next, the 0–4 goes at row 2, column 2 → row 1, column 2. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 3 must add up to 3; 4 must add up to 4; 1 must add up to 1; = must all be the same number; 10 must add up to 10.

3
4
3
4
1
=
10
4
2
5
4
2
1
2
2
0
10
=
5
0
=
3
2
5
Solution as text
  1. 0–1 — 0 at row 5, column 3, 1 at row 6, column 3
  2. 0–2 — 0 at row 2, column 3, 2 at row 3, column 3
  3. 0–3 — 0 at row 7, column 2, 3 at row 7, column 3
  4. 0–4 — 0 at row 2, column 2, 4 at row 1, column 2
  5. 0–5 — 0 at row 2, column 4, 5 at row 3, column 4
  6. 1–2 — 1 at row 6, column 2, 2 at row 5, column 2
  7. 1–3 — 1 at row 2, column 1, 3 at row 1, column 1
  8. 1–4 — 1 at row 4, column 4, 4 at row 5, column 4
  9. 1–5 — 1 at row 6, column 1, 5 at row 7, column 1
  10. 2–3 — 2 at row 8, column 2, 3 at row 8, column 1
  11. 2–4 — 2 at row 4, column 3, 4 at row 4, column 2
  12. 2–5 — 2 at row 5, column 1, 5 at row 4, column 1
  13. 3–4 — 3 at row 1, column 3, 4 at row 1, column 4
  14. 3–5 — 3 at row 8, column 3, 5 at row 8, column 4
  15. 4–5 — 4 at row 3, column 2, 5 at row 3, column 1
  16. 3–6 — 3 at row 7, column 4, 6 at row 6, column 4

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Pips is a game by The New York Times. This page is an independent solving guide and is not affiliated with, endorsed by, or sponsored by The New York Times Company. Puzzle layouts are described here for the purpose of commentary and help.