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NYT Pips answers — Monday, July 27, 2026

Pips #344 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Rodolfo Kurchan · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

Jump to: Easy · Medium · Hard

Easy Pips answer — July 27, 2026

3×4 board · 5 dominoes · 7 regions · by Ian Livengood

The easy board runs 3 rows by 4 columns: 5 dominoes to place across 7 regions. The mix is 3 sum regions, 2 "less than", 2 free regions. The two-cell region at row 3, column 2 adds to 11: the only split is 5 + 6.. After that, the pair at row 1, column 1 adds to 6; list the ways to make 6 with the rack you have.. Rack check: 2 doubles, 2 sixes.

Hints

Hint 1 — where to start

The two-cell region at row 3, column 2 adds to 11: the only split is 5 + 6.

Hint 2 — first domino

Place the 5–5 domino with its 5 at row 2, column 2 and its 5 at row 3, column 2.

Hint 3 — second domino

Next, the 3–3 goes at row 1, column 1 → row 1, column 2. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 6 must add up to 6; <3 must add up to less than 3; 9 must add up to 9; 11 must add up to 11; <4 must add up to less than 4.

6
<3
9
11
<4
Solution as text
  1. 6–4 — 6 at row 3, column 1, 4 at row 2, column 1
  2. 2–4 — 2 at row 1, column 4, 4 at row 1, column 3
  3. 6–3 — 6 at row 3, column 3, 3 at row 3, column 4
  4. 5–5 — 5 at row 2, column 2, 5 at row 3, column 2
  5. 3–3 — 3 at row 1, column 1, 3 at row 1, column 2

Medium Pips answer — July 27, 2026

4×4 board · 7 dominoes · 8 regions · by Rodolfo Kurchan

7 dominoes, 8 regions, a 4×4 grid — that's the medium puzzle for July 27, 2026. The mix is 2 sum regions, 3 "all equal", 1 "less than", 2 free regions. Best foothold — the "=" region starting at row 2, column 3 has 3 cells that must all match — every 0 in the puzzle should come here.. After that, the "=" pair at row 1, column 1 needs two identical pips — a double, or matching halves from two dominoes.. Rack check: 3 blank halves, 3 sixes.

Hints

Hint 1 — where to start

The "=" region starting at row 2, column 3 has 3 cells that must all match — every 0 in the puzzle should come here.

Hint 2 — first domino

Place the 0–3 domino with its 0 at row 2, column 3 and its 3 at row 1, column 3.

Hint 3 — second domino

Next, the 3–6 goes at row 1, column 2 → row 1, column 1. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; <3 must add up to less than 3; 10 must add up to 10.

=
=
<3
=
10
10
Solution as text
  1. 6–5 — 6 at row 2, column 1, 5 at row 3, column 1
  2. 0–3 — 0 at row 2, column 3, 3 at row 1, column 3
  3. 6–2 — 6 at row 2, column 4, 2 at row 1, column 4
  4. 4–0 — 4 at row 3, column 4, 0 at row 3, column 3
  5. 2–5 — 2 at row 4, column 2, 5 at row 4, column 1
  6. 3–6 — 3 at row 1, column 2, 6 at row 1, column 1
  7. 0–2 — 0 at row 4, column 3, 2 at row 4, column 4

Hard Pips answer — July 27, 2026

6×9 board · 16 dominoes · 17 regions · by Rodolfo Kurchan

16 dominoes, 17 regions, a 6×9 grid — that's the hard puzzle for July 27, 2026. Rules on the board: 10 sum regions, 4 "all equal", 2 "greater than", 1 free region. Best foothold — the single cell at row 1, column 3 is marked 4, so it can only hold a 4. After that, the single cell at row 1, column 9 is marked 4, so it can only hold a 4. Rack check: 1 double, 8 blank halves, 3 sixes.

Hints

Hint 1 — where to start

The single cell at row 1, column 3 is marked 4, so it can only hold a 4. Find the domino with a 4 that fits there.

Hint 2 — first domino

Place the 2–4 domino with its 2 at row 1, column 2 and its 4 at row 1, column 3.

Hint 3 — second domino

Next, the 4–5 goes at row 1, column 9 → row 2, column 9. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 3 must add up to 3; 4 must add up to 4; 0 must add up to 0; = must all be the same number; 2 must add up to 2.

3
4
4
0
=
0
=
=
2
>4
=
0
4
>4
0
4
Solution as text
  1. 2–4 — 2 at row 1, column 2, 4 at row 1, column 3
  2. 0–0 — 0 at row 2, column 1, 0 at row 3, column 1
  3. 1–5 — 1 at row 3, column 7, 5 at row 3, column 8
  4. 0–3 — 0 at row 4, column 8, 3 at row 4, column 7
  5. 6–2 — 6 at row 4, column 3, 2 at row 4, column 4
  6. 5–0 — 5 at row 3, column 9, 0 at row 4, column 9
  7. 6–1 — 6 at row 2, column 3, 1 at row 2, column 2
  8. 0–4 — 0 at row 6, column 6, 4 at row 6, column 7
  9. 2–5 — 2 at row 3, column 5, 5 at row 4, column 5
  10. 0–1 — 0 at row 6, column 2, 1 at row 6, column 3
  11. 2–3 — 2 at row 5, column 4, 3 at row 5, column 3
  12. 4–5 — 4 at row 1, column 9, 5 at row 2, column 9
  13. 0–2 — 0 at row 2, column 4, 2 at row 3, column 4
  14. 3–1 — 3 at row 4, column 6, 1 at row 3, column 6
  15. 6–0 — 6 at row 3, column 3, 0 at row 3, column 2
  16. 5–3 — 5 at row 5, column 8, 3 at row 5, column 7

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