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NYT Pips answers — Friday, July 24, 2026

Pips #341 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Rodolfo Kurchan · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

Jump to: Easy · Medium · Hard

Easy Pips answer — July 24, 2026

3×6 board · 5 dominoes · 7 regions · by Ian Livengood

The easy board runs 3 rows by 6 columns: 5 dominoes to place across 7 regions. The mix is 2 sum regions, 1 "all equal", 1 "greater than", 3 free regions. The single cell at row 3, column 3 is marked 2, so it can only hold a 2. After that, the single cell marked ">5" at row 2, column 2 must be a 6.. Rack check: 1 double, 3 blank halves, 1 six.

Hints

Hint 1 — where to start

The single cell at row 3, column 3 is marked 2, so it can only hold a 2. Find the domino with a 2 that fits there.

Hint 2 — first domino

Place the 3–2 domino with its 3 at row 3, column 4 and its 2 at row 3, column 3.

Hint 3 — second domino

Next, the 6–2 goes at row 2, column 2 → row 2, column 1. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; 9 must add up to 9; >5 must add up to more than 5; 2 must add up to 2.

=
9
>5
2
Solution as text
  1. 0–0 — 0 at row 1, column 2, 0 at row 1, column 3
  2. 6–2 — 6 at row 2, column 2, 2 at row 2, column 1
  3. 5–0 — 5 at row 1, column 5, 0 at row 1, column 4
  4. 4–2 — 4 at row 2, column 5, 2 at row 2, column 6
  5. 3–2 — 3 at row 3, column 4, 2 at row 3, column 3

Medium Pips answer — July 24, 2026

4×5 board · 7 dominoes · 10 regions · by Rodolfo Kurchan

7 dominoes, 10 regions, a 4×5 grid — that's the medium puzzle for July 24, 2026. You're working with 1 sum region, 1 "all equal", 5 "greater than", 3 free regions. The "=" pair at row 2, column 3 needs two identical pips — a double, or matching halves from two dominoes.. After that, the pair at row 3, column 1 adds to 3; list the ways to make 3 with the rack you have.. Rack check: 2 doubles, 3 blank halves, 3 sixes.

Hints

Hint 1 — where to start

The "=" pair at row 2, column 3 needs two identical pips — a double, or matching halves from two dominoes.

Hint 2 — first domino

Place the 3–1 domino with its 3 at row 2, column 2 and its 1 at row 2, column 3.

Hint 3 — second domino

Next, the 2–3 goes at row 3, column 1 → row 2, column 1. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: >0 must add up to more than 0; >1 must add up to more than 1; = must all be the same number; >7 must add up to more than 7; 3 must add up to 3.

>0
>1
=
>7
3
>3
>4
Solution as text
  1. 3–1 — 3 at row 2, column 2, 1 at row 2, column 3
  2. 6–6 — 6 at row 2, column 4, 6 at row 3, column 4
  3. 2–3 — 2 at row 3, column 1, 3 at row 2, column 1
  4. 0–0 — 0 at row 1, column 1, 0 at row 1, column 2
  5. 4–1 — 4 at row 3, column 2, 1 at row 3, column 3
  6. 0–1 — 0 at row 1, column 4, 1 at row 1, column 5
  7. 1–6 — 1 at row 4, column 1, 6 at row 4, column 2

Hard Pips answer — July 24, 2026

6×9 board · 13 dominoes · 19 regions · by Rodolfo Kurchan

The hard board runs 6 rows by 9 columns: 13 dominoes to place across 19 regions. The mix is 9 sum regions, 3 "all equal", 5 "greater than", 2 free regions. The single cell at row 3, column 1 is marked 5, so it can only hold a 5. After that, the single cell at row 3, column 4 is marked 1, so it can only hold a 1. Rack check: 1 double, 7 blank halves, 1 six.

Hints

Hint 1 — where to start

The single cell at row 3, column 1 is marked 5, so it can only hold a 5. Find the domino with a 5 that fits there.

Hint 2 — first domino

Place the 0–5 domino with its 0 at row 3, column 2 and its 5 at row 3, column 1.

Hint 3 — second domino

Next, the 1–3 goes at row 3, column 4 → row 3, column 3. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; >4 must add up to more than 4; >2 must add up to more than 2; 5 must add up to 5; 1 must add up to 1.

=
>4
>2
=
=
5
1
2
>3
4
>2
3
>4
6
6
0
2
Solution as text
  1. 2–0 — 2 at row 6, column 4, 0 at row 6, column 3
  2. 5–3 — 5 at row 5, column 8, 3 at row 4, column 8
  3. 2–1 — 2 at row 6, column 7, 1 at row 6, column 8
  4. 0–5 — 0 at row 3, column 2, 5 at row 3, column 1
  5. 4–3 — 4 at row 3, column 6, 3 at row 4, column 6
  6. 0–0 — 0 at row 3, column 8, 0 at row 3, column 9
  7. 4–5 — 4 at row 3, column 7, 5 at row 4, column 7
  8. 4–0 — 4 at row 1, column 9, 0 at row 2, column 9
  9. 1–3 — 1 at row 3, column 4, 3 at row 3, column 3
  10. 0–6 — 0 at row 1, column 2, 6 at row 1, column 3
  11. 4–1 — 4 at row 5, column 4, 1 at row 4, column 4
  12. 0–3 — 0 at row 2, column 2, 3 at row 2, column 3
  13. 2–3 — 2 at row 3, column 5, 3 at row 4, column 5

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