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NYT Pips answers — Thursday, July 16, 2026
Pips #333 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Rodolfo Kurchan · Hard by Rodolfo Kurchan
Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.
Easy Pips answer — July 16, 2026
2×7 board · 5 dominoes · 5 regions · by Ian Livengood
Easy today is a 2×7 board with 5 dominoes and 5 regions. Rules on the board: 3 sum regions, 1 "greater than", 1 free region. The way in: the single cell marked ">5" at row 1, column 1 must be a 6.. After that, three cells adding to 1 at row 1, column 5 means mostly zeros. Rack check: 4 doubles, 2 blank halves, 2 sixes.
Hints
Hint 1 — where to start
The single cell marked ">5" at row 1, column 1 must be a 6.
Hint 2 — first domino
Place the 6–6 domino with its 6 at row 1, column 1 and its 6 at row 2, column 1.
Hint 3 — second domino
Next, the 0–0 goes at row 1, column 5 → row 2, column 5. From there the rest should fall into place.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: >5 must add up to more than 5; 6 must add up to 6; 1 must add up to 1; 16 must add up to 16.
Solution as text
6 · 3 3 0 · · 6 5 5 · 0 1 4
- 5–5 — 5 at row 2, column 2, 5 at row 2, column 3
- 6–6 — 6 at row 1, column 1, 6 at row 2, column 1
- 4–1 — 4 at row 2, column 7, 1 at row 2, column 6
- 3–3 — 3 at row 1, column 3, 3 at row 1, column 4
- 0–0 — 0 at row 1, column 5, 0 at row 2, column 5
Medium Pips answer — July 16, 2026
5×5 board · 7 dominoes · 7 regions · by Rodolfo Kurchan
Medium today is a 5×5 board with 7 dominoes and 7 regions. Rules on the board: 4 sum regions, 1 "all equal", 2 free regions. The way in: the "=" region starting at row 2, column 2 has 3 cells that must all match — every 3 in the puzzle should come here.. After that, the pair at row 1, column 1 adds to 10; list the ways to make 10 with the rack you have.. Rack check: 2 doubles, 1 blank half, 2 sixes.
Hints
Hint 1 — where to start
The "=" region starting at row 2, column 2 has 3 cells that must all match — every 3 in the puzzle should come here.
Hint 2 — first domino
Place the 3–3 domino with its 3 at row 2, column 2 and its 3 at row 2, column 3.
Hint 3 — second domino
Next, the 5–5 goes at row 1, column 1 → row 1, column 2. From there the rest should fall into place.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: 10 must add up to 10; = must all be the same number.
Solution as text
5 5 · · · 1 3 3 · · 5 5 3 6 · · 4 6 4 1 · · 0 · ·
- 3–6 — 3 at row 3, column 3, 6 at row 3, column 4
- 5–5 — 5 at row 1, column 1, 5 at row 1, column 2
- 1–5 — 1 at row 2, column 1, 5 at row 3, column 1
- 4–5 — 4 at row 4, column 2, 5 at row 3, column 2
- 3–3 — 3 at row 2, column 2, 3 at row 2, column 3
- 0–6 — 0 at row 5, column 3, 6 at row 4, column 3
- 1–4 — 1 at row 4, column 5, 4 at row 4, column 4
Hard Pips answer — July 16, 2026
6×8 board · 15 dominoes · 14 regions · by Rodolfo Kurchan
Hard today is a 6×8 board with 15 dominoes and 14 regions. You're working with 3 sum regions, 5 "all equal", 3 "less than", 2 "greater than", 1 free region. The single cell at row 4, column 7 is marked 6, so it can only hold a 6. After that, the single cell at row 6, column 5 is marked 1, so it can only hold a 1. Rack check: 4 doubles, 8 blank halves, 1 six.
Hints
Hint 1 — where to start
The single cell at row 4, column 7 is marked 6, so it can only hold a 6. Find the domino with a 6 that fits there.
Hint 2 — first domino
Place the 0–6 domino with its 0 at row 4, column 8 and its 6 at row 4, column 7.
Hint 3 — second domino
Next, the 0–1 goes at row 5, column 5 → row 6, column 5. From there the rest should fall into place.
Solution
Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; <3 must add up to less than 3; >3 must add up to more than 3; >4 must add up to more than 4; 2 must add up to 2.
Solution as text
1 · · · 3 · 3 1 1 1 · 2 3 · 3 5 5 4 4 4 3 · 3 0 0 · 4 · 2 · 6 0 2 · · · 0 · 4 0 0 · · · 1 · 0 0
- 0–0 — 0 at row 5, column 8, 0 at row 6, column 8
- 0–1 — 0 at row 5, column 5, 1 at row 6, column 5
- 0–2 — 0 at row 6, column 1, 2 at row 5, column 1
- 0–3 — 0 at row 3, column 8, 3 at row 3, column 7
- 0–4 — 0 at row 6, column 7, 4 at row 5, column 7
- 0–5 — 0 at row 4, column 1, 5 at row 3, column 1
- 0–6 — 0 at row 4, column 8, 6 at row 4, column 7
- 1–1 — 1 at row 1, column 1, 1 at row 2, column 1
- 1–3 — 1 at row 1, column 8, 3 at row 1, column 7
- 1–4 — 1 at row 2, column 2, 4 at row 3, column 2
- 2–3 — 2 at row 4, column 5, 3 at row 3, column 5
- 2–4 — 2 at row 2, column 4, 4 at row 3, column 4
- 3–3 — 3 at row 1, column 5, 3 at row 2, column 5
- 3–5 — 3 at row 2, column 7, 5 at row 2, column 8
- 4–4 — 4 at row 3, column 3, 4 at row 4, column 3
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