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NYT Pips answers — Wednesday, July 8, 2026

Pips #325 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Ian Livengood · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

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Easy Pips answer — July 8, 2026

4×4 board · 5 dominoes · 6 regions · by Ian Livengood

Easy today is a 4×4 board with 5 dominoes and 6 regions. The mix is 1 sum region, 2 "all equal", 2 "less than", 1 free region. The two-cell region at row 1, column 2 adds to 11: the only split is 5 + 6.. After that, the "=" region starting at row 3, column 2 has 3 cells that must all match — every 2 in the puzzle should come here.. Rack check: 1 double, 2 blank halves, 1 six.

Hints

Hint 1 — where to start

The two-cell region at row 1, column 2 adds to 11: the only split is 5 + 6.

Hint 2 — first domino

Place the 6–3 domino with its 6 at row 1, column 2 and its 3 at row 1, column 3.

Hint 3 — second domino

Next, the 2–2 goes at row 3, column 2 → row 4, column 2. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 11 must add up to 11; <4 must add up to less than 4; <6 must add up to less than 6; = must all be the same number.

11
<4
<6
=
=
Solution as text
  1. 4–5 — 4 at row 2, column 1, 5 at row 2, column 2
  2. 2–2 — 2 at row 3, column 2, 2 at row 4, column 2
  3. 0–1 — 0 at row 3, column 4, 1 at row 2, column 4
  4. 0–2 — 0 at row 4, column 4, 2 at row 4, column 3
  5. 6–3 — 6 at row 1, column 2, 3 at row 1, column 3

Medium Pips answer — July 8, 2026

4×5 board · 7 dominoes · 7 regions · by Ian Livengood

Medium today is a 4×5 board with 7 dominoes and 7 regions. You're working with 3 sum regions, 1 "all equal", 3 "greater than". The "=" pair at row 2, column 1 needs two identical pips — a double, or matching halves from two dominoes.. After that, the pair at row 3, column 2 adds to 6; list the ways to make 6 with the rack you have.. Rack check: 2 doubles, 1 blank half, 1 six.

Hints

Hint 1 — where to start

The "=" pair at row 2, column 1 needs two identical pips — a double, or matching halves from two dominoes.

Hint 2 — first domino

Place the 4–1 domino with its 4 at row 2, column 1 and its 1 at row 2, column 2.

Hint 3 — second domino

Next, the 3–4 goes at row 3, column 2 → row 3, column 1. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: >3 must add up to more than 3; = must all be the same number; 3 must add up to 3; 12 must add up to 12; 6 must add up to 6.

>3
=
3
12
6
>4
>4
Solution as text
  1. 3–4 — 3 at row 3, column 2, 4 at row 3, column 1
  2. 3–3 — 3 at row 3, column 4, 3 at row 4, column 4
  3. 6–5 — 6 at row 3, column 5, 5 at row 4, column 5
  4. 1–1 — 1 at row 2, column 3, 1 at row 2, column 4
  5. 4–0 — 4 at row 1, column 5, 0 at row 2, column 5
  6. 4–1 — 4 at row 2, column 1, 1 at row 2, column 2
  7. 3–5 — 3 at row 4, column 2, 5 at row 4, column 3

Hard Pips answer — July 8, 2026

6×9 board · 13 dominoes · 15 regions · by Rodolfo Kurchan

13 dominoes, 15 regions, a 6×9 grid — that's the hard puzzle for July 8, 2026. You're working with 8 sum regions, 3 "all equal", 2 "greater than", 2 free regions. The way in: the single cell at row 4, column 8 is marked 1, so it can only hold a 1. After that, the two-cell region at row 3, column 1 adds to 1: the only split is 0 + 1.. Rack check: 2 doubles, 8 blank halves, 4 sixes.

Hints

Hint 1 — where to start

The single cell at row 4, column 8 is marked 1, so it can only hold a 1. Find the domino with a 1 that fits there.

Hint 2 — first domino

Place the 1–5 domino with its 1 at row 4, column 8 and its 5 at row 4, column 7.

Hint 3 — second domino

Next, the 1–2 goes at row 3, column 1 → row 2, column 1. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 4 must add up to 4; = must all be the same number; 1 must add up to 1; 3 must add up to 3; 10 must add up to 10.

4
=
1
3
=
10
1
4
>0
10
5
>4
=
Solution as text
  1. 0–2 — 0 at row 1, column 2, 2 at row 1, column 1
  2. 5–0 — 5 at row 5, column 7, 0 at row 6, column 7
  3. 1–2 — 1 at row 3, column 1, 2 at row 2, column 1
  4. 0–4 — 0 at row 6, column 8, 4 at row 6, column 9
  5. 6–6 — 6 at row 4, column 9, 6 at row 5, column 9
  6. 0–0 — 0 at row 1, column 3, 0 at row 1, column 4
  7. 1–5 — 1 at row 4, column 8, 5 at row 4, column 7
  8. 0–6 — 0 at row 2, column 9, 6 at row 3, column 9
  9. 3–1 — 3 at row 6, column 2, 1 at row 6, column 1
  10. 4–2 — 4 at row 5, column 5, 2 at row 4, column 5
  11. 0–3 — 0 at row 4, column 1, 3 at row 5, column 1
  12. 2–6 — 2 at row 6, column 3, 6 at row 6, column 4
  13. 1–0 — 1 at row 3, column 5, 0 at row 2, column 5

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