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NYT Pips answers — Sunday, July 5, 2026

Pips #322 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Ian Livengood · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

Jump to: Easy · Medium · Hard

Easy Pips answer — July 5, 2026

3×4 board · 5 dominoes · 6 regions · by Ian Livengood

Easy today is a 3×4 board with 5 dominoes and 6 regions. Rules on the board: 5 sum regions, 1 "all equal". Best foothold — the single cell at row 1, column 3 is marked 2, so it can only hold a 2. After that, the single cell at row 2, column 1 is marked 2, so it can only hold a 2. Rack check: 2 sixes.

Hints

Hint 1 — where to start

The single cell at row 1, column 3 is marked 2, so it can only hold a 2. Find the domino with a 2 that fits there.

Hint 2 — first domino

Place the 2–6 domino with its 2 at row 1, column 3 and its 6 at row 1, column 4.

Hint 3 — second domino

Next, the 2–5 goes at row 2, column 1 → row 1, column 1. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 9 must add up to 9; 2 must add up to 2; = must all be the same number; 8 must add up to 8.

9
2
=
2
2
8
Solution as text
  1. 1–4 — 1 at row 2, column 2, 4 at row 1, column 2
  2. 2–6 — 2 at row 1, column 3, 6 at row 1, column 4
  3. 3–1 — 3 at row 3, column 3, 1 at row 3, column 2
  4. 2–5 — 2 at row 2, column 1, 5 at row 1, column 1
  5. 5–6 — 5 at row 3, column 4, 6 at row 2, column 4

Medium Pips answer — July 5, 2026

2×8 board · 8 dominoes · 10 regions · by Ian Livengood

8 dominoes, 10 regions, a 2×8 grid — that's the medium puzzle for July 5, 2026. You're working with 5 sum regions, 3 "all equal", 1 "greater than", 1 free region. The way in: the single cell at row 1, column 1 is marked 0, so it can only hold a 0. After that, the single cell at row 1, column 3 is marked 1, so it can only hold a 1. Rack check: 2 blank halves, 2 sixes.

Hints

Hint 1 — where to start

The single cell at row 1, column 1 is marked 0, so it can only hold a 0. Find the domino with a 0 that fits there.

Hint 2 — first domino

Place the 0–5 domino with its 0 at row 1, column 1 and its 5 at row 1, column 2.

Hint 3 — second domino

Next, the 1–6 goes at row 1, column 3 → row 1, column 4. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 0 must add up to 0; 1 must add up to 1; >10 must add up to more than 10; 10 must add up to 10; 4 must add up to 4.

0
1
>10
10
4
1
=
=
=
Solution as text
  1. 3–5 — 3 at row 2, column 3, 5 at row 2, column 4
  2. 1–3 — 1 at row 2, column 1, 3 at row 2, column 2
  3. 2–5 — 2 at row 2, column 6, 5 at row 1, column 6
  4. 2–0 — 2 at row 2, column 7, 0 at row 2, column 8
  5. 1–6 — 1 at row 1, column 3, 6 at row 1, column 4
  6. 0–5 — 0 at row 1, column 1, 5 at row 1, column 2
  7. 5–4 — 5 at row 1, column 7, 4 at row 1, column 8
  8. 5–6 — 5 at row 2, column 5, 6 at row 1, column 5

Hard Pips answer — July 5, 2026

6×7 board · 13 dominoes · 15 regions · by Rodolfo Kurchan

Hard today is a 6×7 board with 13 dominoes and 15 regions. You're working with 8 sum regions, 2 "all equal", 2 "less than", 2 "greater than", 1 free region. The single cell at row 4, column 2 is marked 1, so it can only hold a 1. After that, the single cell at row 4, column 6 is marked 1, so it can only hold a 1. Rack check: 3 doubles, 3 blank halves, 6 sixes.

Hints

Hint 1 — where to start

The single cell at row 4, column 2 is marked 1, so it can only hold a 1. Find the domino with a 1 that fits there.

Hint 2 — first domino

Place the 3–1 domino with its 3 at row 4, column 1 and its 1 at row 4, column 2.

Hint 3 — second domino

Next, the 1–6 goes at row 4, column 6 → row 5, column 6. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; 8 must add up to 8; >10 must add up to more than 10; >3 must add up to more than 3; 1 must add up to 1.

=
8
>10
>3
=
8
1
1
<2
10
11
<3
6
6
Solution as text
  1. 0–0 — 0 at row 5, column 3, 0 at row 5, column 4
  2. 1–6 — 1 at row 4, column 6, 6 at row 5, column 6
  3. 2–2 — 2 at row 1, column 1, 2 at row 2, column 1
  4. 0–3 — 0 at row 5, column 2, 3 at row 5, column 1
  5. 5–6 — 5 at row 6, column 2, 6 at row 6, column 1
  6. 3–4 — 3 at row 1, column 4, 4 at row 2, column 4
  7. 5–2 — 5 at row 1, column 3, 2 at row 1, column 2
  8. 6–4 — 6 at row 6, column 7, 4 at row 6, column 6
  9. 5–3 — 5 at row 3, column 7, 3 at row 3, column 6
  10. 2–6 — 2 at row 6, column 3, 6 at row 6, column 4
  11. 3–1 — 3 at row 4, column 1, 1 at row 4, column 2
  12. 6–6 — 6 at row 2, column 2, 6 at row 2, column 3
  13. 2–3 — 2 at row 3, column 2, 3 at row 3, column 1

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