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NYT Pips answers — Thursday, June 25, 2026

Pips #312 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Rodolfo Kurchan · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

Jump to: Easy · Medium · Hard

Easy Pips answer — June 25, 2026

4×4 board · 5 dominoes · 6 regions · by Ian Livengood

Easy today is a 4×4 board with 5 dominoes and 6 regions. Rules on the board: 1 sum region, 1 "all equal", 3 "less than", 1 free region. Best foothold — the "=" region starting at row 1, column 2 has 3 cells that must all match — every 3 in the puzzle should come here.. After that, three cells adding to 16 at row 3, column 2 needs big pips — at least one 6.. Rack check: 1 double, 2 sixes.

Hints

Hint 1 — where to start

The "=" region starting at row 1, column 2 has 3 cells that must all match — every 3 in the puzzle should come here.

Hint 2 — first domino

Place the 4–3 domino with its 4 at row 2, column 2 and its 3 at row 1, column 2.

Hint 3 — second domino

Next, the 2–6 goes at row 3, column 1 → row 3, column 2. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; <5 must add up to less than 5; <3 must add up to less than 3; 16 must add up to 16.

=
<5
<3
<3
16
Solution as text
  1. 2–3 — 2 at row 2, column 4, 3 at row 2, column 3
  2. 5–5 — 5 at row 3, column 3, 5 at row 4, column 3
  3. 4–3 — 4 at row 2, column 2, 3 at row 1, column 2
  4. 6–3 — 6 at row 1, column 4, 3 at row 1, column 3
  5. 2–6 — 2 at row 3, column 1, 6 at row 3, column 2

Medium Pips answer — June 25, 2026

4×5 board · 7 dominoes · 8 regions · by Rodolfo Kurchan

7 dominoes, 8 regions, a 4×5 grid — that's the medium puzzle for June 25, 2026. You're working with 6 sum regions, 1 "all equal", 1 free region. The way in: the single cell at row 4, column 1 is marked 5, so it can only hold a 5. After that, the single cell at row 4, column 4 is marked 3, so it can only hold a 3. Rack check: 2 doubles, 2 blank halves.

Hints

Hint 1 — where to start

The single cell at row 4, column 1 is marked 5, so it can only hold a 5. Find the domino with a 5 that fits there.

Hint 2 — first domino

Place the 0–5 domino with its 0 at row 3, column 1 and its 5 at row 4, column 1.

Hint 3 — second domino

Next, the 5–3 goes at row 4, column 5 → row 4, column 4. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 6 must add up to 6; 5 must add up to 5; = must all be the same number; 3 must add up to 3.

6
5
=
3
6
5
3
Solution as text
  1. 1–1 — 1 at row 4, column 2, 1 at row 4, column 3
  2. 0–5 — 0 at row 3, column 1, 5 at row 4, column 1
  3. 3–3 — 3 at row 1, column 2, 3 at row 2, column 2
  4. 1–0 — 1 at row 3, column 3, 0 at row 3, column 2
  5. 2–3 — 2 at row 1, column 3, 3 at row 1, column 4
  6. 4–1 — 4 at row 3, column 4, 1 at row 3, column 5
  7. 5–3 — 5 at row 4, column 5, 3 at row 4, column 4

Hard Pips answer — June 25, 2026

7×9 board · 15 dominoes · 16 regions · by Rodolfo Kurchan

Hard today is a 7×9 board with 15 dominoes and 16 regions. You're working with 7 sum regions, 3 "all equal", 1 "less than", 2 "greater than", 3 free regions. The single cell at row 7, column 8 is marked 4, so it can only hold a 4. After that, the two-cell region at row 2, column 9 adds to 0: both cells must be 0. Rack check: 4 doubles, 6 blank halves, 5 sixes.

Hints

Hint 1 — where to start

The single cell at row 7, column 8 is marked 4, so it can only hold a 4. Find the domino with a 4 that fits there.

Hint 2 — first domino

Place the 4–2 domino with its 4 at row 7, column 8 and its 2 at row 7, column 7.

Hint 3 — second domino

Next, the 0–4 goes at row 2, column 9 → row 2, column 8. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: >4 must add up to more than 4; = must all be the same number; 0 must add up to 0; 11 must add up to 11; <4 must add up to less than 4.

>4
=
0
11
<4
0
=
=
4
5
>4
13
4
Solution as text
  1. 2–0 — 2 at row 3, column 8, 0 at row 3, column 9
  2. 6–4 — 6 at row 1, column 7, 4 at row 2, column 7
  3. 0–0 — 0 at row 4, column 1, 0 at row 5, column 1
  4. 2–2 — 2 at row 4, column 4, 2 at row 4, column 5
  5. 5–5 — 5 at row 4, column 6, 5 at row 5, column 6
  6. 0–6 — 0 at row 4, column 2, 6 at row 3, column 2
  7. 4–2 — 4 at row 7, column 8, 2 at row 7, column 7
  8. 6–5 — 6 at row 5, column 4, 5 at row 5, column 5
  9. 0–4 — 0 at row 2, column 9, 4 at row 2, column 8
  10. 1–5 — 1 at row 2, column 1, 5 at row 3, column 1
  11. 6–6 — 6 at row 7, column 2, 6 at row 7, column 3
  12. 4–1 — 4 at row 6, column 7, 1 at row 5, column 7
  13. 0–3 — 0 at row 4, column 3, 3 at row 5, column 3
  14. 1–2 — 1 at row 6, column 2, 2 at row 5, column 2
  15. 3–4 — 3 at row 4, column 7, 4 at row 3, column 7

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