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NYT Pips answers — Monday, June 15, 2026

Pips #302 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Rodolfo Kurchan · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

Jump to: Easy · Medium · Hard

Easy Pips answer — June 15, 2026

5×3 board · 5 dominoes · 6 regions · by Ian Livengood

5 dominoes, 6 regions, a 5×3 grid — that's the easy puzzle for June 15, 2026. The mix is 4 sum regions, 2 free regions. Best foothold — the two-cell region at row 1, column 1 adds to 0: both cells must be 0. After that, the pair at row 2, column 1 adds to 2; list the ways to make 2 with the rack you have.. Rack check: 2 doubles, 2 blank halves.

Hints

Hint 1 — where to start

The two-cell region at row 1, column 1 adds to 0: both cells must be 0. That's the 0–0 domino, or two 0s from different dominoes.

Hint 2 — first domino

Place the 0–1 domino with its 0 at row 1, column 1 and its 1 at row 2, column 1.

Hint 3 — second domino

Next, the 3–4 goes at row 3, column 1 → row 4, column 1. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 0 must add up to 0; 2 must add up to 2; 4 must add up to 4; 6 must add up to 6.

0
2
4
6
Solution as text
  1. 0–1 — 0 at row 1, column 1, 1 at row 2, column 1
  2. 3–0 — 3 at row 1, column 3, 0 at row 1, column 2
  3. 3–4 — 3 at row 3, column 1, 4 at row 4, column 1
  4. 1–1 — 1 at row 2, column 2, 1 at row 3, column 2
  5. 2–2 — 2 at row 4, column 2, 2 at row 5, column 2

Medium Pips answer — June 15, 2026

6×3 board · 6 dominoes · 8 regions · by Rodolfo Kurchan

The medium board runs 6 rows by 3 columns: 6 dominoes to place across 8 regions. Rules on the board: 4 sum regions, 1 "less than", 3 free regions. The way in: the pair at row 2, column 1 adds to 9; list the ways to make 9 with the rack you have.. After that, the pair at row 2, column 3 adds to 8; list the ways to make 8 with the rack you have.. Rack check: 2 doubles, 1 blank half, 2 sixes.

Hints

Hint 1 — where to start

The pair at row 2, column 1 adds to 9; list the ways to make 9 with the rack you have.

Hint 2 — first domino

Place the 4–4 domino with its 4 at row 1, column 1 and its 4 at row 2, column 1.

Hint 3 — second domino

Next, the 6–5 goes at row 1, column 3 → row 2, column 3. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 9 must add up to 9; 8 must add up to 8; 6 must add up to 6; <3 must add up to less than 3.

9
8
8
6
<3
Solution as text
  1. 3–3 — 3 at row 3, column 3, 3 at row 4, column 3
  2. 6–0 — 6 at row 5, column 1, 0 at row 6, column 1
  3. 3–4 — 3 at row 5, column 3, 4 at row 6, column 3
  4. 6–5 — 6 at row 1, column 3, 5 at row 2, column 3
  5. 4–4 — 4 at row 1, column 1, 4 at row 2, column 1
  6. 5–2 — 5 at row 3, column 1, 2 at row 4, column 1

Hard Pips answer — June 15, 2026

10×7 board · 12 dominoes · 13 regions · by Rodolfo Kurchan

Hard today is a 10×7 board with 12 dominoes and 13 regions. You're working with 4 sum regions, 2 "all equal", 1 "less than", 3 "greater than", 3 free regions. The single cell at row 7, column 5 is marked 5, so it can only hold a 5. After that, the two-cell region at row 3, column 5 adds to 11: the only split is 5 + 6.. Rack check: 3 doubles, 5 blank halves, 3 sixes.

Hints

Hint 1 — where to start

The single cell at row 7, column 5 is marked 5, so it can only hold a 5. Find the domino with a 5 that fits there.

Hint 2 — first domino

Place the 5–1 domino with its 5 at row 7, column 5 and its 1 at row 7, column 4.

Hint 3 — second domino

Next, the 0–5 goes at row 3, column 6 → row 3, column 5. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: <4 must add up to less than 4; = must all be the same number; >2 must add up to more than 2; 11 must add up to 11; 5 must add up to 5.

<4
=
>2
>2
11
11
11
>2
=
5
Solution as text
  1. 5–6 — 5 at row 5, column 5, 6 at row 4, column 5
  2. 2–2 — 2 at row 2, column 1, 2 at row 3, column 1
  3. 5–1 — 5 at row 7, column 5, 1 at row 7, column 4
  4. 0–5 — 0 at row 3, column 6, 5 at row 3, column 5
  5. 1–1 — 1 at row 7, column 3, 1 at row 8, column 3
  6. 3–0 — 3 at row 2, column 5, 0 at row 1, column 5
  7. 4–2 — 4 at row 2, column 3, 2 at row 2, column 2
  8. 3–6 — 3 at row 5, column 7, 6 at row 5, column 6
  9. 0–0 — 0 at row 1, column 6, 0 at row 1, column 7
  10. 0–6 — 0 at row 5, column 3, 6 at row 5, column 2
  11. 5–2 — 5 at row 5, column 1, 2 at row 4, column 1
  12. 2–1 — 2 at row 10, column 3, 1 at row 9, column 3

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