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NYT Pips answers — Saturday, February 7, 2026

Pips #174 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Ian Livengood · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

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Easy Pips answer — February 7, 2026

3×4 board · 4 dominoes · 4 regions · by Ian Livengood

4 dominoes, 4 regions, a 3×4 grid — that's the easy puzzle for February 7, 2026. You're working with 1 sum region, 2 "less than", 1 "greater than". The way in: the "<1" region at row 2, column 1 leaves almost no room: every cell must be 0.. Rack check: 1 double, 1 blank half, 5 sixes.

Hints

Hint 1 — where to start

The "<1" region at row 2, column 1 leaves almost no room: every cell must be 0.

Hint 2 — first domino

Place the 6–0 domino with its 6 at row 2, column 2 and its 0 at row 2, column 1.

Hint 3 — second domino

Next, the 4–6 goes at row 1, column 4 → row 1, column 3. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 30 must add up to 30; >3 must add up to more than 3; <1 must add up to less than 1; <3 must add up to less than 3.

30
>3
<1
<3
Solution as text
  1. 6–6 — 6 at row 3, column 2, 6 at row 3, column 3
  2. 6–0 — 6 at row 2, column 2, 0 at row 2, column 1
  3. 4–6 — 4 at row 1, column 4, 6 at row 1, column 3
  4. 6–2 — 6 at row 2, column 3, 2 at row 2, column 4

Medium Pips answer — February 7, 2026

3×6 board · 8 dominoes · 9 regions · by Ian Livengood

The medium board runs 3 rows by 6 columns: 8 dominoes to place across 9 regions. Rules on the board: 5 sum regions, 2 "all equal", 1 "less than", 1 free region. The way in: the single cell at row 1, column 1 is marked 6, so it can only hold a 6. After that, the single cell at row 1, column 6 is marked 3, so it can only hold a 3. Rack check: 2 doubles, 1 blank half, 2 sixes.

Hints

Hint 1 — where to start

The single cell at row 1, column 1 is marked 6, so it can only hold a 6. Find the domino with a 6 that fits there.

Hint 2 — first domino

Place the 6–1 domino with its 6 at row 1, column 1 and its 1 at row 2, column 1.

Hint 3 — second domino

Next, the 3–1 goes at row 1, column 6 → row 2, column 6. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 6 must add up to 6; = must all be the same number; 3 must add up to 3; 7 must add up to 7; 2 must add up to 2.

6
=
3
7
7
2
=
<2
Solution as text
  1. 5–4 — 5 at row 3, column 3, 4 at row 3, column 4
  2. 2–3 — 2 at row 2, column 3, 3 at row 2, column 2
  3. 6–1 — 6 at row 1, column 1, 1 at row 2, column 1
  4. 1–1 — 1 at row 1, column 3, 1 at row 1, column 4
  5. 0–4 — 0 at row 2, column 5, 4 at row 2, column 4
  6. 4–4 — 4 at row 3, column 5, 4 at row 3, column 6
  7. 6–4 — 6 at row 3, column 1, 4 at row 3, column 2
  8. 3–1 — 3 at row 1, column 6, 1 at row 2, column 6

Hard Pips answer — February 7, 2026

6×6 board · 10 dominoes · 10 regions · by Rodolfo Kurchan

10 dominoes, 10 regions, a 6×6 grid — that's the hard puzzle for February 7, 2026. You're working with 10 sum regions. The two-cell region at row 4, column 5 adds to 11: the only split is 5 + 6.. After that, the pair at row 1, column 3 adds to 5; list the ways to make 5 with the rack you have.. Rack check: 2 doubles, 1 six.

Hints

Hint 1 — where to start

The two-cell region at row 4, column 5 adds to 11: the only split is 5 + 6.

Hint 2 — first domino

Place the 5–4 domino with its 5 at row 4, column 5 and its 4 at row 3, column 5.

Hint 3 — second domino

Next, the 4–2 goes at row 1, column 3 → row 1, column 4. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 5 must add up to 5; 3 must add up to 3; 8 must add up to 8; 9 must add up to 9; 7 must add up to 7.

5
3
8
9
7
2
4
11
6
10
Solution as text
  1. 4–1 — 4 at row 2, column 2, 1 at row 2, column 3
  2. 6–5 — 6 at row 5, column 5, 5 at row 5, column 4
  3. 4–2 — 4 at row 1, column 3, 2 at row 1, column 4
  4. 1–1 — 1 at row 3, column 6, 1 at row 4, column 6
  5. 4–4 — 4 at row 3, column 1, 4 at row 3, column 2
  6. 1–3 — 1 at row 4, column 2, 3 at row 4, column 1
  7. 5–4 — 5 at row 4, column 5, 4 at row 3, column 5
  8. 4–3 — 4 at row 5, column 3, 3 at row 5, column 2
  9. 2–5 — 2 at row 6, column 3, 5 at row 6, column 4
  10. 1–5 — 1 at row 2, column 4, 5 at row 2, column 5

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