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NYT Pips answers — Friday, November 28, 2025

Pips #103 · Edited by Ian Livengood · Easy by Ian Livengood · Medium by Rodolfo Kurchan · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

Jump to: Easy · Medium · Hard

Easy Pips answer — November 28, 2025

4×4 board · 5 dominoes · 6 regions · by Ian Livengood

The easy board runs 4 rows by 4 columns: 5 dominoes to place across 6 regions. The mix is 1 sum region, 2 "all equal", 1 "less than", 2 free regions. Best foothold — the single cell at row 4, column 1 is marked 6, so it can only hold a 6. After that, the "=" region starting at row 1, column 3 has 3 cells that must all match — every 3 in the puzzle should come here.. Rack check: 1 blank half, 1 six.

Hints

Hint 1 — where to start

The single cell at row 4, column 1 is marked 6, so it can only hold a 6. Find the domino with a 6 that fits there.

Hint 2 — first domino

Place the 1–6 domino with its 1 at row 3, column 1 and its 6 at row 4, column 1.

Hint 3 — second domino

Next, the 3–5 goes at row 1, column 3 → row 1, column 4. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; <3 must add up to less than 3; 6 must add up to 6.

=
<3
=
6
Solution as text
  1. 3–5 — 3 at row 1, column 3, 5 at row 1, column 4
  2. 1–0 — 1 at row 3, column 2, 0 at row 4, column 2
  3. 3–1 — 3 at row 2, column 3, 1 at row 3, column 3
  4. 1–6 — 1 at row 3, column 1, 6 at row 4, column 1
  5. 3–2 — 3 at row 2, column 2, 2 at row 2, column 1

Medium Pips answer — November 28, 2025

4×5 board · 7 dominoes · 8 regions · by Rodolfo Kurchan

7 dominoes, 8 regions, a 4×5 grid — that's the medium puzzle for November 28, 2025. You're working with 4 sum regions, 1 "all equal", 1 "greater than", 2 free regions. The way in: the "=" pair at row 3, column 1 needs two identical pips — a double, or matching halves from two dominoes.. After that, the pair at row 1, column 4 adds to 10; list the ways to make 10 with the rack you have.. Rack check: 2 doubles, 2 sixes.

Hints

Hint 1 — where to start

The "=" pair at row 3, column 1 needs two identical pips — a double, or matching halves from two dominoes.

Hint 2 — first domino

Place the 1–4 domino with its 1 at row 4, column 1 and its 4 at row 3, column 1.

Hint 3 — second domino

Next, the 5–5 goes at row 1, column 4 → row 2, column 4. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: >4 must add up to more than 4; 10 must add up to 10; 9 must add up to 9; = must all be the same number; 4 must add up to 4.

>4
10
9
=
4
6
Solution as text
  1. 6–3 — 6 at row 1, column 1, 3 at row 2, column 1
  2. 4–3 — 4 at row 3, column 2, 3 at row 4, column 2
  3. 4–6 — 4 at row 2, column 3, 6 at row 2, column 2
  4. 1–4 — 1 at row 4, column 1, 4 at row 3, column 1
  5. 2–3 — 2 at row 3, column 3, 3 at row 4, column 3
  6. 5–5 — 5 at row 1, column 4, 5 at row 2, column 4
  7. 1–1 — 1 at row 3, column 4, 1 at row 3, column 5

Hard Pips answer — November 28, 2025

7×4 board · 9 dominoes · 9 regions · by Rodolfo Kurchan

The hard board runs 7 rows by 4 columns: 9 dominoes to place across 9 regions. The mix is 7 sum regions, 2 free regions. The single cell at row 3, column 1 is marked 0, so it can only hold a 0. After that, the two-cell region at row 4, column 3 adds to 11: the only split is 5 + 6.. Rack check: 4 doubles, 3 blank halves, 4 sixes.

Hints

Hint 1 — where to start

The single cell at row 3, column 1 is marked 0, so it can only hold a 0. Find the domino with a 0 that fits there.

Hint 2 — first domino

Place the 0–6 domino with its 0 at row 3, column 1 and its 6 at row 2, column 1.

Hint 3 — second domino

Next, the 3–5 goes at row 4, column 2 → row 4, column 3. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 10 must add up to 10; 4 must add up to 4; 12 must add up to 12; 0 must add up to 0; 11 must add up to 11.

10
4
12
0
11
12
12
Solution as text
  1. 3–2 — 3 at row 1, column 3, 2 at row 1, column 4
  2. 0–0 — 0 at row 4, column 1, 0 at row 5, column 1
  3. 6–6 — 6 at row 6, column 1, 6 at row 7, column 1
  4. 1–4 — 1 at row 1, column 2, 4 at row 1, column 1
  5. 5–5 — 5 at row 2, column 4, 5 at row 3, column 4
  6. 3–5 — 3 at row 4, column 2, 5 at row 4, column 3
  7. 0–6 — 0 at row 3, column 1, 6 at row 2, column 1
  8. 4–4 — 4 at row 6, column 4, 4 at row 7, column 4
  9. 6–4 — 6 at row 5, column 3, 4 at row 5, column 4

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