What is the answer to the easy NYT Pips for October 20, 2025?

Solution grid (rows top to bottom, · = no cell): · · 3 / · · 3 / · · 3 / 0 · 0 / 6 · 2 / 5 4 6. Dominoes: 0–3 at row 4, column 3 to row 3, column 3; 4–5 at row 6, column 2 to row 6, column 1; 3–3 at row 1, column 3 to row 2, column 3; 6–2 at row 6, column 3 to row 5, column 3; 6–0 at row 5, column 1 to row 4, column 1.

What is the answer to the medium NYT Pips for October 20, 2025?

Solution grid (rows top to bottom, · = no cell): 1 5 0 5 4 5 / 1 2 0 4 4 1 / · · 0 4 · · / · · 0 2 · · / · · 3 2 · · / · · 3 6 · ·. Dominoes: 3–3 at row 5, column 3 to row 6, column 3; 1–2 at row 2, column 1 to row 2, column 2; 5–1 at row 1, column 2 to row 1, column 1; 2–0 at row 4, column 4 to row 4, column 3; 0–0 at row 2, column 3 to row 3, column 3; 0–5 at row 1, column 3 to row 1, column 4; 6–2 at row 6, column 4 to row 5, column 4; 4–5 at row 1, column 5 to row 1, column 6; 1–4 at row 2, column 6 to row 2, column 5; 4–4 at row 2, column 4 to row 3, column 4.

What is the answer to the hard NYT Pips for October 20, 2025?

Solution grid (rows top to bottom, · = no cell): 2 6 · · · · / · 1 6 · · · / · · 4 6 3 4 / · · 6 0 2 3 / · 2 1 · · · / · · 3 5 · ·. Dominoes: 5–3 at row 6, column 4 to row 6, column 3; 1–2 at row 5, column 3 to row 5, column 2; 6–1 at row 2, column 3 to row 2, column 2; 6–0 at row 4, column 3 to row 4, column 4; 6–2 at row 1, column 2 to row 1, column 1; 6–4 at row 3, column 4 to row 3, column 3; 3–2 at row 3, column 5 to row 4, column 5; 4–3 at row 3, column 6 to row 4, column 6.

Grid Puzzles › Pips › NYT Pips answers

NYT Pips answers — Monday, October 20, 2025

Pips #64 · Edited by Ian Livengood · Easy by Rodolfo Kurchan · Medium by Rodolfo Kurchan · Hard by Heidi Erwin

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

Jump to: Easy · Medium · Hard

Easy Pips answer — October 20, 2025

6×3 board · 5 dominoes · 5 regions · by Rodolfo Kurchan

5 dominoes, 5 regions, a 6×3 grid — that's the easy puzzle for October 20, 2025. You're working with 3 sum regions, 1 free region. The two-cell region at row 5, column 1 adds to 11: the only split is 5 + 6.. After that, the pair at row 6, column 2 adds to 10; list the ways to make 10 with the rack you have.. Rack check: 1 double, 2 blank halves, 2 sixes.

Hints

Hint 1 — where to start

The two-cell region at row 5, column 1 adds to 11: the only split is 5 + 6.

Hint 2 — first domino

Place the 6–0 domino with its 6 at row 5, column 1 and its 0 at row 4, column 1.

Hint 3 — second domino

Next, the 4–5 goes at row 6, column 2 → row 6, column 1. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 9 must add up to 9; ≠ must all be different; 11 must add up to 11; 10 must add up to 10.

≠

Solution as text

· · 3
· · 3
· · 3
0 · 0
6 · 2
5 4 6

0–3 — 0 at row 4, column 3, 3 at row 3, column 3
4–5 — 4 at row 6, column 2, 5 at row 6, column 1
3–3 — 3 at row 1, column 3, 3 at row 2, column 3
6–2 — 6 at row 6, column 3, 2 at row 5, column 3
6–0 — 6 at row 5, column 1, 0 at row 4, column 1

Medium Pips answer — October 20, 2025

6×6 board · 10 dominoes · 11 regions · by Rodolfo Kurchan

Medium today is a 6×6 board with 10 dominoes and 11 regions. The mix is 3 sum regions, 2 "all equal", 4 "greater than", 2 free regions. The "=" region starting at row 1, column 5 has 4 cells that must all match — every 4 in the puzzle should come here.. After that, the "=" pair at row 5, column 3 needs two identical pips — a double, or matching halves from two dominoes.. Rack check: 3 doubles, 4 blank halves, 1 six.

Hints

Hint 1 — where to start

The "=" region starting at row 1, column 5 has 4 cells that must all match — every 4 in the puzzle should come here.

Hint 2 — first domino

Place the 4–5 domino with its 4 at row 1, column 5 and its 5 at row 1, column 6.

Hint 3 — second domino

Next, the 3–3 goes at row 5, column 3 → row 6, column 3. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 2 must add up to 2; >4 must add up to more than 4; 0 must add up to 0; = must all be the same number; 4 must add up to 4.

Solution as text

1 5 0 5 4 5
1 2 0 4 4 1
· · 0 4 · ·
· · 0 2 · ·
· · 3 2 · ·
· · 3 6 · ·

3–3 — 3 at row 5, column 3, 3 at row 6, column 3
1–2 — 1 at row 2, column 1, 2 at row 2, column 2
5–1 — 5 at row 1, column 2, 1 at row 1, column 1
2–0 — 2 at row 4, column 4, 0 at row 4, column 3
0–0 — 0 at row 2, column 3, 0 at row 3, column 3
0–5 — 0 at row 1, column 3, 5 at row 1, column 4
6–2 — 6 at row 6, column 4, 2 at row 5, column 4
4–5 — 4 at row 1, column 5, 5 at row 1, column 6
1–4 — 1 at row 2, column 6, 4 at row 2, column 5
4–4 — 4 at row 2, column 4, 4 at row 3, column 4

Hard Pips answer — October 20, 2025

6×6 board · 8 dominoes · 7 regions · by Heidi Erwin

8 dominoes, 7 regions, a 6×6 grid — that's the hard puzzle for October 20, 2025. You're working with 2 sum regions, 2 "greater than", 2 free regions. The single cell at row 2, column 3 is marked 6, so it can only hold a 6. Rack check: 1 blank half, 4 sixes.

Hints

Hint 1 — where to start

The single cell at row 2, column 3 is marked 6, so it can only hold a 6. Find the domino with a 6 that fits there.

Hint 2 — first domino

Place the 6–1 domino with its 6 at row 2, column 3 and its 1 at row 2, column 2.

Hint 3 — second domino

Next, the 6–0 goes at row 4, column 3 → row 4, column 4. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: >6 must add up to more than 6; 6 must add up to 6; ≠ must all be different; 13 must add up to 13; >2 must add up to more than 2.

≠

Solution as text

2 6 · · · ·
· 1 6 · · ·
· · 4 6 3 4
· · 6 0 2 3
· 2 1 · · ·
· · 3 5 · ·

5–3 — 5 at row 6, column 4, 3 at row 6, column 3
1–2 — 1 at row 5, column 3, 2 at row 5, column 2
6–1 — 6 at row 2, column 3, 1 at row 2, column 2
6–0 — 6 at row 4, column 3, 0 at row 4, column 4
6–2 — 6 at row 1, column 2, 2 at row 1, column 1
6–4 — 6 at row 3, column 4, 4 at row 3, column 3
3–2 — 3 at row 3, column 5, 2 at row 4, column 5
4–3 — 4 at row 3, column 6, 3 at row 4, column 6

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