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NYT Pips answers — Wednesday, September 24, 2025

Pips #38 · Edited by Ian Livengood · Easy by Rodolfo Kurchan · Medium by Rodolfo Kurchan · Hard by Rodolfo Kurchan

Stuck on today's New York Times Pips? Below are three progressive hints for each difficulty, then the full solution as a tap-to-reveal board. Hints first — the answer only when you want it.

Jump to: Easy · Medium · Hard

Easy Pips answer — September 24, 2025

3×3 board · 4 dominoes · 3 regions · by Rodolfo Kurchan

Easy today is a 3×3 board with 4 dominoes and 3 regions. Rules on the board: 2 sum regions, 1 free region. Best foothold — the pair at row 2, column 3 adds to 10; list the ways to make 10 with the rack you have.. Rack check: 1 double, 1 blank half, 1 six.

Hints

Hint 1 — where to start

The pair at row 2, column 3 adds to 10; list the ways to make 10 with the rack you have.

Hint 2 — first domino

Place the 0–4 domino with its 0 at row 1, column 3 and its 4 at row 2, column 3.

Hint 3 — second domino

Next, the 4–6 goes at row 3, column 2 → row 3, column 3. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: 6 must add up to 6; 10 must add up to 10.

6
10
Solution as text
  1. 2–2 — 2 at row 1, column 1, 2 at row 1, column 2
  2. 0–4 — 0 at row 1, column 3, 4 at row 2, column 3
  3. 4–6 — 4 at row 3, column 2, 6 at row 3, column 3
  4. 5–2 — 5 at row 3, column 1, 2 at row 2, column 1

Medium Pips answer — September 24, 2025

3×6 board · 8 dominoes · 6 regions · by Rodolfo Kurchan

The medium board runs 3 rows by 6 columns: 8 dominoes to place across 6 regions. You're working with 1 sum region, 3 "all equal", 1 "greater than", 1 free region. The way in: the single cell at row 1, column 5 is marked 2, so it can only hold a 2. After that, the "=" region starting at row 1, column 1 has 4 cells that must all match — every 4 in the puzzle should come here.. Rack check: 2 doubles, 2 sixes.

Hints

Hint 1 — where to start

The single cell at row 1, column 5 is marked 2, so it can only hold a 2. Find the domino with a 2 that fits there.

Hint 2 — first domino

Place the 3–2 domino with its 3 at row 1, column 6 and its 2 at row 1, column 5.

Hint 3 — second domino

Next, the 6–4 goes at row 1, column 2 → row 1, column 1. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; >10 must add up to more than 10; 2 must add up to 2.

=
>10
=
2
=
Solution as text
  1. 6–4 — 6 at row 1, column 2, 4 at row 1, column 1
  2. 3–2 — 3 at row 1, column 6, 2 at row 1, column 5
  3. 4–5 — 4 at row 2, column 3, 5 at row 2, column 4
  4. 3–5 — 3 at row 3, column 5, 5 at row 3, column 4
  5. 3–3 — 3 at row 2, column 6, 3 at row 3, column 6
  6. 5–6 — 5 at row 1, column 4, 6 at row 1, column 3
  7. 4–4 — 4 at row 2, column 1, 4 at row 3, column 1
  8. 2–4 — 2 at row 3, column 3, 4 at row 3, column 2

Hard Pips answer — September 24, 2025

4×7 board · 10 dominoes · 10 regions · by Rodolfo Kurchan

10 dominoes, 10 regions, a 4×7 grid — that's the hard puzzle for September 24, 2025. You're working with 4 sum regions, 2 "all equal", 2 "less than", 1 free region. The way in: the single cell at row 1, column 7 is marked 1, so it can only hold a 1. After that, the single cell at row 2, column 7 is marked 4, so it can only hold a 4. Rack check: 4 doubles, 2 blank halves, 2 sixes.

Hints

Hint 1 — where to start

The single cell at row 1, column 7 is marked 1, so it can only hold a 1. Find the domino with a 1 that fits there.

Hint 2 — first domino

Place the 1–3 domino with its 1 at row 1, column 7 and its 3 at row 1, column 6.

Hint 3 — second domino

Next, the 4–4 goes at row 2, column 7 → row 3, column 7. From there the rest should fall into place.

Solution

Tap any cell to reveal its pips, or reveal the whole board. Region rules: = must all be the same number; 10 must add up to 10; ≠ must all be different; 1 must add up to 1; 4 must add up to 4.

=
10
≠
1
4
=
<1
<1
6
Solution as text
  1. 0–5 — 0 at row 4, column 2, 5 at row 3, column 2
  2. 2–2 — 2 at row 3, column 1, 2 at row 4, column 1
  3. 4–4 — 4 at row 2, column 7, 4 at row 3, column 7
  4. 5–3 — 5 at row 1, column 5, 3 at row 1, column 4
  5. 0–6 — 0 at row 4, column 4, 6 at row 4, column 5
  6. 5–5 — 5 at row 2, column 5, 5 at row 2, column 6
  7. 1–3 — 1 at row 1, column 7, 3 at row 1, column 6
  8. 3–3 — 3 at row 2, column 4, 3 at row 3, column 4
  9. 6–1 — 6 at row 4, column 7, 1 at row 4, column 6
  10. 2–3 — 2 at row 3, column 6, 3 at row 3, column 5

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